What is the limit as x approaches 9-of \sqrt[4]{9-x} ?

The limit as x approaches 9-of \sqrt[4]{9-x} is 0

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limit as x approaches 9-of \sqrt[4]{9-x}

0

Solution steps

Plug in the value

x = 9

Simplify

= 0

\frac{d}{d x} ((2 x + 5)^{\frac{1}{2}})

\frac{d}{d t} (6 cos (2 t))

y = x^{3}, y = x^{2} - 9 x, [- 1, 1]

\int (3 e^{5 x} - \frac{7}{x} + \frac{4}{1 + x ^{2}}) d x

\frac{d}{d x} (tan (x^{2} - 1))

What is the limit as x approaches 9-of \sqrt[4]{9-x} ?
The limit as x approaches 9-of \sqrt[4]{9-x} is 0