What is the limit as x approaches 0 of (sin^6(x))/x ?

The limit as x approaches 0 of (sin^6(x))/x is 0

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limit as x approaches 0 of (sin^6(x))/x

x \to 0 lim (\frac{sin ^{6} ( x )}{x})

0

Solution steps

x \to 0 lim (\frac{sin ^{6} ( x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{6 sin ^{5} ( x ) cos ( x )}{1})

= x \to 0 lim (\frac{6 sin ^{5} ( x ) cos ( x )}{1})

Plug in the value

x = 0

= \frac{6 sin ^{5} ( 0 ) cos ( 0 )}{1}

Simplify

\frac{6 sin ^{5} ( 0 ) cos ( 0 )}{1} : 0

= 0

\frac{\partial}{\partial y} (x^{2} sin^{2} (y))

\frac{d}{d x} (1^{\frac{1}{3}})

x^{2} y^{^{''}} + 3 x y^{^{'}} + y = \frac{1}{x}

\frac{d}{d x} ((e^{x}) (cos (x)))

(6.1) (1.1)

What is the limit as x approaches 0 of (sin^6(x))/x ?
The limit as x approaches 0 of (sin^6(x))/x is 0