What is the limit as x approaches 0 of 1/x+ln(x) ?

The limit as x approaches 0 of 1/x+ln(x) is Does not exist

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limit as x approaches 0 of 1/x+ln(x)

x \to 0 lim (\frac{1}{x} + ln (x))

Does not exist

Solution steps

x \to 0 lim (\frac{1}{x} + ln (x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x} + ln (x)) = \infty

x \to 0 - lim (\frac{1}{x} + ln (x)) =

Does not exist

= Does not exist

x \to 0 lim (\frac{4 x}{e ^{x} - 1})

x \to 1 lim (x^{2} - 4 x + 5)

x \to 2 + lim (\frac{3 x + 1}{2 - x})

x \to 0 lim ((1 - cos (x))^{x})

x \to 1 lim (x - 4)

What is the limit as x approaches 0 of 1/x+ln(x) ?
The limit as x approaches 0 of 1/x+ln(x) is Does not exist