What is (\partial)/(\partial z)(xz-7yz+4) ?

The answer to (\partial)/(\partial z)(xz-7yz+4) is x-7y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial z)(xz-7yz+4)

\frac{\partial}{\partial z} (x z - 7 yz + 4)

x - 7 y

Solution steps

\frac{\partial}{\partial z} (x z - 7 yz + 4)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x z) - \frac{\partial}{\partial z} (7 yz) + \frac{\partial}{\partial z} (4)

\frac{\partial}{\partial z} (x z) = x

\frac{\partial}{\partial z} (7 yz) = 7 y

\frac{\partial}{\partial z} (4) = 0

= x - 7 y + 0

Simplify

= x - 7 y

\int e^{- s t} cos (2 t) d t

x^{2} + 3

2 x^{3} 25 - x^{2}

x \to 0 + lim (1)

x \to 1 lim (\frac{e ^{x}}{x - 1})

What is (\partial)/(\partial z)(xz-7yz+4) ?
The answer to (\partial)/(\partial z)(xz-7yz+4) is x-7y