What is the limit as x approaches 0 of (x^4-2)/(x^3) ?

The limit as x approaches 0 of (x^4-2)/(x^3) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (x^4-2)/(x^3)

x \to 0 lim (\frac{x ^{4} - 2}{x ^{3}})

diverges

Solution steps

x \to 0 lim (\frac{x ^{4} - 2}{x ^{3}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{x ^{4} - 2}{x ^{3}}) = - \infty

x \to 0 - lim (\frac{x ^{4} - 2}{x ^{3}}) = \infty

= diverges

x \to 0 + lim (\frac{1}{1 + ln ( x )})

x \to 4 lim (4 x^{3} - 3 x^{2} + 1)

x \to 5 lim (x + 6)

x \to 0 lim (1 - \frac{∣ x ∣}{x})

x \to 5 lim (2 x + 3)

What is the limit as x approaches 0 of (x^4-2)/(x^3) ?
The limit as x approaches 0 of (x^4-2)/(x^3) is diverges