What is the limit as n approaches infinity of (-2)^n ?

The limit as n approaches infinity of (-2)^n is diverges

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limit as n approaches infinity of (-2)^n

n \to \infty lim ((- 2)^{n})

diverges

Solution steps

n \to \infty lim ((- 2)^{n})

Apply exponent rule:

(a \cdot b)^{n} = a^{n} \cdot b^{n}

(- 2)^{n} = (- 1)^{n} (2)^{n}

= n \to \infty lim ((- 1)^{n} \cdot 2^{n})

Apply Limit Divergence Criterion:

diverges

= diverges

x \to \infty + lim (sin (x))

x \to 2 - lim (\frac{2 - x}{∣ 2 - x ∣})

x \to - 2 - lim (x^{2} - 4 x + 6)

x \to - π lim (sin (- \frac{x}{2}))

x \to 0 - lim (x e^{\frac{1}{x}} + 1)

What is the limit as n approaches infinity of (-2)^n ?
The limit as n approaches infinity of (-2)^n is diverges