What is the limit as q approaches 2 of (4q^2-q+2)/8 ?

The limit as q approaches 2 of (4q^2-q+2)/8 is 2

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limit as q approaches 2 of (4q^2-q+2)/8

q \to 2 lim (\frac{4 q ^{2} - q + 2}{8})

2

Solution steps

q \to 2 lim (\frac{4 q ^{2} - q + 2}{8})

Plug in the value

q = 2

= \frac{4 \cdot 2 ^{2} - 2 + 2}{8}

Simplify

= 2

z \to 2 lim (\frac{z + 7}{z ^{2} - 4})

x \to 10 lim (ln (x))

x \to 0 lim (\frac{4 x ^{3}}{5 x ^{4}})

x \to \frac{1}{3} lim (\frac{x ^{2}}{x ^{4}})

x \to (a + 1) lim (x - 1)

What is the limit as q approaches 2 of (4q^2-q+2)/8 ?
The limit as q approaches 2 of (4q^2-q+2)/8 is 2