What is the derivative of sqrt(1-9x^2)arccos(3x) ?

The derivative of sqrt(1-9x^2)arccos(3x) is -(9xarccos(3x))/(sqrt(1-9x^2))-3

What is the first derivative of sqrt(1-9x^2)arccos(3x) ?

The first derivative of sqrt(1-9x^2)arccos(3x) is -(9xarccos(3x))/(sqrt(1-9x^2))-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

1 - 9 x^{2} arccos (3 x)

- \frac{9 x arccos ( 3 x )}{1 - 9 x ^{2}} - 3

Solution steps

\frac{d}{d x} (1 - 9 x^{2} arccos (3 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 1 - 9 x^{2}, g = arccos (3 x)

= \frac{d}{d x} (1 - 9 x^{2}) arccos (3 x) + \frac{d}{d x} (arccos (3 x)) 1 - 9 x^{2}

\frac{d}{d x} (1 - 9 x^{2}) = - \frac{9 x}{1 - 9 x ^{2}}

\frac{d}{d x} (arccos (3 x)) = - \frac{3}{1 - 9 x ^{2}}

= (- \frac{9 x}{1 - 9 x ^{2}}) arccos (3 x) + (- \frac{3}{1 - 9 x ^{2}}) 1 - 9 x^{2}

Simplify

(- \frac{9 x}{1 - 9 x ^{2}}) arccos (3 x) + (- \frac{3}{1 - 9 x ^{2}}) 1 - 9 x^{2} : - \frac{9 x arccos ( 3 x )}{1 - 9 x ^{2}} - 3

= - \frac{9 x arccos ( 3 x )}{1 - 9 x ^{2}} - 3

n = 2 \sum \infty n

f (t) = e^{3 t s i n (2 t)}

\frac{d}{d x} ((ln ∣ x ∣)^{e} + \frac{x}{11})

25 y^{^{''}} - 10 y^{^{'}} + y = 0

lo g_{3} (2 x + 5)

What is the derivative of sqrt(1-9x^2)arccos(3x) ?
The derivative of sqrt(1-9x^2)arccos(3x) is -(9xarccos(3x))/(sqrt(1-9x^2))-3
What is the first derivative of sqrt(1-9x^2)arccos(3x) ?
The first derivative of sqrt(1-9x^2)arccos(3x) is -(9xarccos(3x))/(sqrt(1-9x^2))-3