What is the limit as x approaches 0 of 5x^2ln(x) ?

The limit as x approaches 0 of 5x^2ln(x) is Does not exist

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limit as x approaches 0 of 5x^2ln(x)

x \to 0 lim (5 x^{2} ln (x))

Does not exist

Solution steps

x \to 0 lim (5 x^{2} ln (x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (5 x^{2} ln (x)) = 0

x \to 0 - lim (5 x^{2} ln (x)) =

Does not exist

= Does not exist

x \to 0 - lim (ln (2 x^{2} + e))

x \to \infty lim (1 0^{x} + 2)

x \to 2 lim (\frac{2 x - 4}{x ^{2} - 4})

x \to 3 lim (2 x - 5)

x \to \frac{π}{6} lim (cot (4 x))

What is the limit as x approaches 0 of 5x^2ln(x) ?
The limit as x approaches 0 of 5x^2ln(x) is Does not exist