What is the limit as x approaches 0 of (x^2-x)/(2x) ?

The limit as x approaches 0 of (x^2-x)/(2x) is -1/2

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limit as x approaches 0 of (x^2-x)/(2x)

x \to 0 lim (\frac{x ^{2} - x}{2 x})

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

x \to 0 lim (\frac{x ^{2} - x}{2 x})

Simplify

\frac{x ^{2} - x}{2 x} : \frac{1}{2} (x - 1)

= x \to 0 lim (\frac{1}{2} (x - 1))

Plug in the value

x = 0

= \frac{1}{2} (0 - 1)

Simplify

= - \frac{1}{2}

x \to 3 lim (\frac{1}{x ^{2} + 16})

x \to 1 lim (ln (x) \cdot ln (x - 1))

x \to 0 lim ((x + 7)^{2} sin (x))

x \to 4 π lim (cos (x))

x \to 5 lim (\frac{4}{x - 7})

What is the limit as x approaches 0 of (x^2-x)/(2x) ?
The limit as x approaches 0 of (x^2-x)/(2x) is -1/2