What is the d/(dt)(acos(3t)+bsin(3t)) ?

The d/(dt)(acos(3t)+bsin(3t)) is -3asin(3t)+bcos(3t)*3

What is the first d/(dt)(acos(3t)+bsin(3t)) ?

The first d/(dt)(acos(3t)+bsin(3t)) is -3asin(3t)+bcos(3t)*3

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\frac{d}{d t} (a cos (3 t) + b sin (3 t))

- 3 a sin (3 t) + b cos (3 t) \cdot 3

Solution steps

\frac{d}{d t} (a cos (3 t) + b sin (3 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (a cos (3 t)) + \frac{d}{d t} (b sin (3 t))

\frac{d}{d t} (a cos (3 t)) = - 3 a sin (3 t)

\frac{d}{d t} (b sin (3 t)) = b cos (3 t) \cdot 3

= - 3 a sin (3 t) + b cos (3 t) \cdot 3

\frac{\partial}{\partial a} (\frac{a}{sin ( θ )})

\frac{d}{d x} (x arctan (x))

x \frac{d y}{d x} = y + x^{2} + y^{2}

\int sin^{3} (x) x d x

x \to 1 lim (1 + x)

What is the d/(dt)(acos(3t)+bsin(3t)) ?
The d/(dt)(acos(3t)+bsin(3t)) is -3asin(3t)+bcos(3t)*3
What is the first d/(dt)(acos(3t)+bsin(3t)) ?
The first d/(dt)(acos(3t)+bsin(3t)) is -3asin(3t)+bcos(3t)*3