What is the derivative of f(x)=sqrt(2x+9) ?

The derivative of f(x)=sqrt(2x+9) is 1/(sqrt(2x+9))

What is the first derivative of f(x)=sqrt(2x+9) ?

The first derivative of f(x)=sqrt(2x+9) is 1/(sqrt(2x+9))

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derivative of

f (x) = 2 x + 9

\frac{1}{2 x + 9}

Solution steps

\frac{d}{d x} (2 x + 9)

Apply the chain rule:

\frac{1}{2 2 x + 9} \frac{d}{d x} (2 x + 9)

= \frac{1}{2 2 x + 9} \frac{d}{d x} (2 x + 9)

\frac{d}{d x} (2 x + 9) = 2

= \frac{1}{2 2 x + 9} \cdot 2

Simplify

\frac{1}{2 2 x + 9} \cdot 2 : \frac{1}{2 x + 9}

= \frac{1}{2 x + 9}

\int \frac{sin ( 2 x + 1 )}{cos ^{2} ( 2 x + 1 )} d x

\frac{d}{d x} ((2 x + 1)^{3})

f (x) = 4 x - x

\frac{d}{d x} (cos^{3} (\frac{x}{x + 1}))

x \to \infty lim (x - 5)

What is the derivative of f(x)=sqrt(2x+9) ?
The derivative of f(x)=sqrt(2x+9) is 1/(sqrt(2x+9))
What is the first derivative of f(x)=sqrt(2x+9) ?
The first derivative of f(x)=sqrt(2x+9) is 1/(sqrt(2x+9))