What is the limit as x approaches 0 of 2xln(1/x) ?

The limit as x approaches 0 of 2xln(1/x) is Does not exist

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limit as x approaches 0 of 2xln(1/x)

x \to 0 lim (2 x ln (\frac{1}{x}))

Does not exist

Solution steps

x \to 0 lim (2 x ln (\frac{1}{x}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (2 x ln (\frac{1}{x})) = 0

x \to 0 - lim (2 x ln (\frac{1}{x})) =

Does not exist

= Does not exist

x \to 0 lim (\frac{1}{1 - 2 x})

x \to - 7 + lim (\frac{2 x + 1}{x + 7})

x \to 0 lim (\frac{x ^{2} - x}{x ^{2}})

x \to \frac{π}{4} lim (\frac{4 x}{tan ( x )})

x \to - 1 lim (2 x^{3} - \frac{3}{x - 1})

What is the limit as x approaches 0 of 2xln(1/x) ?
The limit as x approaches 0 of 2xln(1/x) is Does not exist