What is the limit as x approaches 0 of xsin(1/(x+y)) ?

The limit as x approaches 0 of xsin(1/(x+y)) is 0

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limit as x approaches 0 of xsin(1/(x+y))

x \to 0 lim (x sin (\frac{1}{x + y}))

0

Solution steps

x \to 0 lim (x sin (\frac{1}{x + y}))

Plug in the value

x = 0

= 0 \cdot sin (\frac{1}{0 + y})

Simplify

= 0

x \to 0 lim (1 0^{x} + 2)

x \to - \infty lim (4 - 5 x)

x \to \infty lim (9 + \frac{6}{x})

x \to - \frac{1}{5} lim (x^{3} + 5 x)

x \to - 2 lim (2 x - x^{2})

What is the limit as x approaches 0 of xsin(1/(x+y)) ?
The limit as x approaches 0 of xsin(1/(x+y)) is 0