What is the limit as x approaches 5 of (x-4)(x^2+8) ?

The limit as x approaches 5 of (x-4)(x^2+8) is 33

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limit as x approaches 5 of (x-4)(x^2+8)

x \to 5 lim ((x - 4) (x^{2} + 8))

33

Solution steps

x \to 5 lim ((x - 4) (x^{2} + 8))

Plug in the value

x = 5

= (5 - 4) (5^{2} + 8)

Simplify

(5 - 4) (5^{2} + 8) : 33

= 33

x \to 5 + lim (x)

x \to - 2 - lim (\frac{x + 3}{x + 2})

x \to 3 lim (4 - 2 x)

x \to 0 lim (1 0^{x + 2})

x \to - 3 lim (x^{3} + 27)

What is the limit as x approaches 5 of (x-4)(x^2+8) ?
The limit as x approaches 5 of (x-4)(x^2+8) is 33