What is the tangent of f(x)= 2/(x+1),\at x=7 ?

The tangent of f(x)= 2/(x+1),\at x=7 is y=-1/32 x+15/32

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 2/(x+1),\at x=7

tangent of

f (x) = \frac{2}{x + 1}, at x = 7

y = - \frac{1}{32} x + \frac{15}{32}

Solution steps

Find the tangent point:

(7, \frac{1}{4})

Find the slope of

f (x) = \frac{2}{x + 1} : \frac{df ( x )}{d x} = - \frac{2}{( x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{2}{x + 1}

x = 7 : m = - \frac{1}{32}

Find the line with slope m=

- \frac{1}{32}

and passing through

(7, \frac{1}{4}) : y = - \frac{1}{32} x + \frac{15}{32}

y = - \frac{1}{32} x + \frac{15}{32}

x \to 0 + lim (\frac{12}{x ^{2}})

\int_{0}^{2} \frac{x ^{2}}{2} d x

\int \frac{3}{4 x - x ^{2}} d x

\int \frac{2 x ^{2} + 2}{( x ^{2} - 2 x + 2 ) ^{2}} d x

g (x) = \frac{6 x ^{2}}{2 - x}

What is the tangent of f(x)= 2/(x+1),\at x=7 ?
The tangent of f(x)= 2/(x+1),\at x=7 is y=-1/32 x+15/32