What is the limit as x approaches 0-of picoth(1/x) ?

The limit as x approaches 0-of picoth(1/x) is -pi

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limit as x approaches 0-of picoth(1/x)

x \to 0 - lim (π coth (\frac{1}{x}))

- π

Decimal Notation

- 3.14159 \dots

Solution steps

x \to 0 - lim (π coth (\frac{1}{x}))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= π \cdot x \to 0 - lim (coth (\frac{1}{x}))

Apply the Limit Chain Rule:

- 1

= π (- 1)

Simplify

= - π

x \to 7 - lim (\frac{∣ x ∣ - x}{x - 7})

x \to 2 lim (\frac{x - 4}{x ^{2} - 4})

x \to 0 lim (\frac{arcsin ( x ) - arctan ( x )}{x ^{3}})

x \to a lim (f (x) (x)^{n})

x \to - 6 lim (10 x + 1)

What is the limit as x approaches 0-of picoth(1/x) ?
The limit as x approaches 0-of picoth(1/x) is -pi