What is the derivative of (x-1^2\sqrt[3]{x+2}) ?

The derivative of (x-1^2\sqrt[3]{x+2}) is 2(x-1)\sqrt[3]{x+2}+((x-1)^2)/(3(x+2)^{2/3)}

What is the first derivative of (x-1^2\sqrt[3]{x+2}) ?

The first derivative of (x-1^2\sqrt[3]{x+2}) is 2(x-1)\sqrt[3]{x+2}+((x-1)^2)/(3(x+2)^{2/3)}

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Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} ((x - 1)^{2}) = 2 (x - 1)

\frac{1}{3 ( x + 2 ) ^{\frac{2}{3}}} (x - 1)^{2} = \frac{( x - 1 ) ^{2}}{3 ( x + 2 ) ^{\frac{2}{3}}}

\frac{3 x ^{\frac{3}{5}} - x}{x - 1}

\int \frac{x + 1}{x ^{2} + 2 x + 5} d x

\int - 5 x^{4} d x

\int csc^{2} (x) - 2 e^{x} d x

\int_{0}^{\frac{1}{4}} \frac{1}{1 + 16 x ^{2}} d x

What is the derivative of (x-1^2\sqrt[3]{x+2}) ?
The derivative of (x-1^2\sqrt[3]{x+2}) is 2(x-1)\sqrt[3]{x+2}+((x-1)^2)/(3(x+2)^{2/3)}
What is the first derivative of (x-1^2\sqrt[3]{x+2}) ?
The first derivative of (x-1^2\sqrt[3]{x+2}) is 2(x-1)\sqrt[3]{x+2}+((x-1)^2)/(3(x+2)^{2/3)}