What is the limit as x approaches 0 of xln(1/(x^2)) ?

The limit as x approaches 0 of xln(1/(x^2)) is diverges

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limit as x approaches 0 of xln(1/(x^2))

x \to 0 lim (x ln (\frac{1}{x ^{2}}))

diverges

Solution steps

x \to 0 lim (x ln (\frac{1}{x ^{2}}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x ln (\frac{1}{x ^{2}})) = 0

x \to 0 - lim (x ln (\frac{1}{x ^{2}})) = 0 \cdot (- Does not exist)

= diverges

x \to 2 lim (\frac{4}{[ - 2 + 4 ] ^{2}})

x \to π lim (x cot (x))

x \to 0 + lim (2 (\frac{1}{x} - cot (x)))

x \to 2 - lim (\frac{x ^{2} - 1}{x - 2})

x \to 3 lim (- 4 x)

What is the limit as x approaches 0 of xln(1/(x^2)) ?
The limit as x approaches 0 of xln(1/(x^2)) is diverges