What is the limit as x approaches 1 of b+1/(x-1) ?

The limit as x approaches 1 of b+1/(x-1) is diverges

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limit as x approaches 1 of b+1/(x-1)

x \to 1 lim (b + \frac{1}{x - 1})

diverges

Solution steps

x \to 1 lim (b + \frac{1}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (b + \frac{1}{x - 1}) = \infty

x \to 1 - lim (b + \frac{1}{x - 1}) = - \infty

= diverges

y = 4 x, y = \frac{4}{x}, x = 4

\frac{1}{s ( s ^{2} + 6 s + 13 )}

x \to 1 lim (10 x + 15)

\int (\frac{x ^{2}}{4} + 2 x + 3) d x

\frac{d}{d x} (\frac{ln ( 6 x )}{6 x})

What is the limit as x approaches 1 of b+1/(x-1) ?
The limit as x approaches 1 of b+1/(x-1) is diverges