What is the slope ofintercept (2,1),(-4,-2) ?

The slope ofintercept (2,1),(-4,-2) is y= 1/2 x+0

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slope ofintercept (2,1),(-4,-2)

slope intercept

(2, 1), (- 4, - 2)

y = \frac{1}{2} x + 0

Solution steps

Compute the slope

(2, 1), (- 4, - 2) : m = \frac{1}{2}

Compute the

y

intercept:

b = 0

Construct the line equation

y = mx + b

where

m = \frac{1}{2}

and

b = 0

y = \frac{1}{2} x + 0

\int 4 x^{2} cos (\frac{x}{5}) d x

x \to 3 - lim (\frac{2}{( x - 3 ) ^{3}})

\int \frac{x - 5}{x + 3} d x

y = (x - 2)^{2}, y = x

f (x) = arcsin (3 x)

What is the slope ofintercept (2,1),(-4,-2) ?
The slope ofintercept (2,1),(-4,-2) is y= 1/2 x+0