What is the limit as x approaches 2 of (x+1)/(4-x^2) ?

The limit as x approaches 2 of (x+1)/(4-x^2) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2 of (x+1)/(4-x^2)

x \to 2 lim (\frac{x + 1}{4 - x ^{2}})

diverges

Solution steps

x \to 2 lim (\frac{x + 1}{4 - x ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{x + 1}{4 - x ^{2}}) = - \infty

x \to 2 - lim (\frac{x + 1}{4 - x ^{2}}) = \infty

= diverges

x \to 4 lim ([\frac{x ^{2} + 4}{5}])

x \to 4 - lim (\frac{x + 1}{x - 4})

x \to - 1 lim (\frac{x ^{3} - x}{x + 1})

x \to 2 lim (5 x + 9)

x \to π lim (sin (\frac{x}{2} - π))

What is the limit as x approaches 2 of (x+1)/(4-x^2) ?
The limit as x approaches 2 of (x+1)/(4-x^2) is diverges