What is the limit as p approaches 2 of sqrt(p^2+p+5) ?

The limit as p approaches 2 of sqrt(p^2+p+5) is square root of 11

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limit as p approaches 2 of sqrt(p^2+p+5)

p \to 2 lim (p^{2} + p + 5)

11

Decimal

3.31662 \dots

Solution steps

p \to 2 lim (p^{2} + p + 5)

Plug in the value

p = 2

= 2^{2} + 2 + 5

Simplify

= 11

x \to \infty lim ((- 5)^{n})

x \to 2 lim (\frac{2 - x}{x ^{3} - 8})

x \to - 2 lim ((x + 4) (x - \frac{1}{2}))

x \to - 4 lim (2 x^{3} + x^{2} + 2)

x \to 0 lim (\frac{0}{sin ^{2} ( x )})

What is the limit as p approaches 2 of sqrt(p^2+p+5) ?
The limit as p approaches 2 of sqrt(p^2+p+5) is square root of 11