What is the tangent of f(x)=4sqrt(x),\at x=25 ?

The tangent of f(x)=4sqrt(x),\at x=25 is y= 2/5 x+10

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tangent of f(x)=4sqrt(x),\at x=25

tangent of

f (x) = 4 x, at x = 25

y = \frac{2}{5} x + 10

Solution steps

Find the tangent point:

(25, 20)

Find the slope of

f (x) = 4 x : \frac{df ( x )}{d x} = \frac{2}{x}

Compute the slope of

f (x) = 4 x

x = 25 : m = \frac{2}{5}

Find the line with slope m=

\frac{2}{5}

and passing through

(25, 20) : y = \frac{2}{5} x + 10

y = \frac{2}{5} x + 10

\frac{\partial}{\partial x} ((t + 1)^{3})

\frac{d}{d x} (sin (cos (x^{2})))

\int \frac{2 x ^{2} + 3}{( x ^{2} + 1 ) ^{2}} d x

(x + y) \frac{d y}{d x} = x - y

\int sec^{4} (x) tan^{3} (x) d x

What is the tangent of f(x)=4sqrt(x),\at x=25 ?
The tangent of f(x)=4sqrt(x),\at x=25 is y= 2/5 x+10