What is the limit as t approaches 5-of (|t-5|)/(t-5) ?

The limit as t approaches 5-of (|t-5|)/(t-5) is -1

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limit as t approaches 5-of (|t-5|)/(t-5)

t \to 5 - lim (\frac{∣ t - 5 ∣}{t - 5})

- 1

Solution steps

t \to 5 - lim (\frac{∣ t - 5 ∣}{t - 5})

t - 5

is negative when

t \to 5 -

. Therefore

∣ t - 5 ∣ = - t + 5

= t \to 5 - lim (\frac{- t + 5}{t - 5})

\frac{- t + 5}{t - 5} = - 1

= t \to 5 - lim (- 1)

x \to a lim c = c

= - 1

x \to 0 lim (\frac{100}{x})

x \to - 1 lim (\frac{3 x + 3}{x + 1})

h \to 0 lim (\frac{sin ( 2 h )}{5 h ^{2} + 7 h})

x \to - 2 lim ([f (x) + 5 g (x)])

x \to 0 lim (\frac{ln ( \frac{1}{x} )}{x})

What is the limit as t approaches 5-of (|t-5|)/(t-5) ?
The limit as t approaches 5-of (|t-5|)/(t-5) is -1