What is the limit as x approaches 5/2 of ln(2x-5) ?

The limit as x approaches 5/2 of ln(2x-5) is Does not exist

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limit as x approaches 5/2 of ln(2x-5)

x \to \frac{5}{2} lim (ln (2 x - 5))

Does not exist

Solution steps

x \to \frac{5}{2} lim (ln (2 x - 5))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to \frac{5}{2} + lim (ln (2 x - 5)) = - \infty

x \to \frac{5}{2} - lim (ln (2 x - 5)) =

Does not exist

= Does not exist

x \to 0.1 lim (\frac{sin ( x )}{x})

x \to e lim (\frac{ln ( x )}{x - e})

x \to 0 - lim (\frac{1}{x} - csc (x))

θ \to \frac{3 π}{2} lim (sin (tan (cos (θ))))

x \to 0 lim (s g (s, x) n (x))

What is the limit as x approaches 5/2 of ln(2x-5) ?
The limit as x approaches 5/2 of ln(2x-5) is Does not exist