What is the integral from-1 to 4 of (x^2+2x-1) ?

The integral from-1 to 4 of (x^2+2x-1) is 95/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 4 of (x^2+2x-1)

\int_{- 1}^{4} (x^{2} + 2 x - 1) d x

\frac{95}{3}

Decimal Notation

31.66666 \dots

Solution steps

\int_{- 1}^{4} x^{2} + 2 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{4} x^{2} d x + \int_{- 1}^{4} 2 x d x - \int_{- 1}^{4} 1 d x

\int_{- 1}^{4} x^{2} d x = \frac{65}{3}

\int_{- 1}^{4} 2 x d x = 15

\int_{- 1}^{4} 1 d x = 5

= \frac{65}{3} + 15 - 5

Simplify

\frac{65}{3} + 15 - 5 : \frac{95}{3}

= \frac{95}{3}

\frac{d}{d x} (- y x)

49 y^{^{''}} + 140 y^{^{'}} + 100 y = 0

x^{2} + 3

\int (3 - x^{2}) 2^{x} d x

ln (x y) + y^{2} = 2 y, (e, 1)

What is the integral from-1 to 4 of (x^2+2x-1) ?
The integral from-1 to 4 of (x^2+2x-1) is 95/3