What is the limit as x approaches+0 of x^{sqrt(x)} ?

The limit as x approaches+0 of x^{sqrt(x)} is Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches+0 of x^{sqrt(x)}

x \to + 0 lim (x^{x})

Does not exist

Solution steps

x \to 0 lim (x^{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x^{x}) = 1

x \to 0 - lim (x^{x}) =

Does not exist

= Does not exist

x \to 0 + lim (- x^{x})

x \to 0 lim ((2 x + 1)^{2})

x \to 5 lim (\frac{2}{( x - 5 ) ^{2}})

x \to - 3 - lim (9 - x^{2})

x \to - 2 lim (\frac{x ^{2} - x - 6}{x - 2})

What is the limit as x approaches+0 of x^{sqrt(x)} ?
The limit as x approaches+0 of x^{sqrt(x)} is Does not exist