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Popular >

derivative of \sqrt[5]{x^2+1}

Solution

Solution

\frac{2 x}{5 ( x ^{2} + 1 ) ^{\frac{4}{5}}}

Solution steps

Apply the chain rule:

\frac{1}{5 ( x ^{2} + 1 ) ^{\frac{4}{5}}} \frac{d}{d x} (x^{2} + 1)

= \frac{1}{5 ( x ^{2} + 1 ) ^{\frac{4}{5}}} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= \frac{1}{5 ( x ^{2} + 1 ) ^{\frac{4}{5}}} \cdot 2 x

Simplify

\frac{1}{5 ( x ^{2} + 1 ) ^{\frac{4}{5}}} \cdot 2 x : \frac{2 x}{5 ( x ^{2} + 1 ) ^{\frac{4}{5}}}

= \frac{2 x}{5 ( x ^{2} + 1 ) ^{\frac{4}{5}}}

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Frequently Asked Questions (FAQ)

What is the derivative of \sqrt[5]{x^2+1} ?
The derivative of \sqrt[5]{x^2+1} is (2x)/(5(x^2+1)^{4/5)}
What is the first derivative of \sqrt[5]{x^2+1} ?
The first derivative of \sqrt[5]{x^2+1} is (2x)/(5(x^2+1)^{4/5)}