What is the limit as x approaches-infinity of e^x-5 ?

The limit as x approaches-infinity of e^x-5 is -5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-infinity of e^x-5

x \to - \infty lim (e^{x} - 5)

- 5

Solution steps

x \to - \infty lim (e^{x} - 5)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - \infty lim (e^{x}) - x \to - \infty lim (5)

x \to - \infty lim (e^{x}) = 0

x \to - \infty lim (5) = 5

= 0 - 5

Simplify

= - 5

x \to 0 lim (\frac{2}{3 + e ^{\frac{1}{x}}})

x \to \infty lim (2 - 3 x^{2})

x \to 0 lim (\frac{4 - 4 cos ( x )}{x ^{2}})

x \to 0 lim (\frac{2 ∣ x ∣}{2 x})

h \to 0 lim (\frac{7 ^{h} - 1}{h})

What is the limit as x approaches-infinity of e^x-5 ?
The limit as x approaches-infinity of e^x-5 is -5