What is the limit as x approaches 0 of 2/(3+e^{1/x)} ?

The limit as x approaches 0 of 2/(3+e^{1/x)} is diverges

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limit as x approaches 0 of 2/(3+e^{1/x)}

x \to 0 lim (\frac{2}{3 + e ^{\frac{1}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{2}{3 + e ^{\frac{1}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{2}{3 + e ^{\frac{1}{x}}}) = 0

x \to 0 - lim (\frac{2}{3 + e ^{\frac{1}{x}}}) = \frac{2}{3}

= diverges

x \to \infty lim (2 - 3 x^{2})

x \to 0 lim (\frac{4 - 4 cos ( x )}{x ^{2}})

x \to 0 lim (\frac{2 ∣ x ∣}{2 x})

h \to 0 lim (\frac{7 ^{h} - 1}{h})

x \to 3 lim (\frac{5 x}{4} + 3)

What is the limit as x approaches 0 of 2/(3+e^{1/x)} ?
The limit as x approaches 0 of 2/(3+e^{1/x)} is diverges