What is the derivative of y=(2x+1)/(3x-4) ?

The derivative of y=(2x+1)/(3x-4) is -(11)/((3x-4)^2)

What is the first derivative of y=(2x+1)/(3x-4) ?

The first derivative of y=(2x+1)/(3x-4) is -(11)/((3x-4)^2)

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derivative of

y = \frac{2 x + 1}{3 x - 4}

- \frac{11}{( 3 x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x + 1}{3 x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x + 1 ) ( 3 x - 4 ) - \frac{d}{d x} ( 3 x - 4 ) ( 2 x + 1 )}{( 3 x - 4 ) ^{2}}

\frac{d}{d x} (2 x + 1) = 2

\frac{d}{d x} (3 x - 4) = 3

= \frac{2 ( 3 x - 4 ) - 3 ( 2 x + 1 )}{( 3 x - 4 ) ^{2}}

Simplify

\frac{2 ( 3 x - 4 ) - 3 ( 2 x + 1 )}{( 3 x - 4 ) ^{2}} : - \frac{11}{( 3 x - 4 ) ^{2}}

= - \frac{11}{( 3 x - 4 ) ^{2}}

\frac{d}{d x} (e^{- \frac{x}{4}})

\int \frac{( x ^{2} )}{49 - x ^{2}} d x

y^{^{''}} - 9 y = 2 t^{2} + 3 t + 9

\frac{d}{d x} (3 x^{2} + e^{2 x} + π^{2})

n = 1 \sum \infty \frac{n}{6 n ^{2} - 5}

What is the derivative of y=(2x+1)/(3x-4) ?
The derivative of y=(2x+1)/(3x-4) is -(11)/((3x-4)^2)
What is the first derivative of y=(2x+1)/(3x-4) ?
The first derivative of y=(2x+1)/(3x-4) is -(11)/((3x-4)^2)