What is the limit as x approaches 0+of (-2ln(x))^x ?

The limit as x approaches 0+of (-2ln(x))^x is Does not exist

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limit as x approaches 0+of (-2ln(x))^x

x \to 0 + lim ((- 2 ln (x))^{x})

Does not exist

Solution steps

x \to 0 + lim ((- 2 ln (x))^{x})

Apply exponent rule:

(a \cdot b)^{n} = a^{n} \cdot b^{n}

(- 2 ln (x))^{x} = (- 1)^{x} (2 ln (x))^{x}

= x \to 0 + lim ((- 1)^{x} (2 ln (x))^{x})

(- 1)^{x} (2 ln (x))^{x}

undefined for

x

approaching

0

from the right

= Does not exist

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x \to 0 lim (\frac{ln ( x ^{4} )}{x})

x \to + 0 lim (s g (s, x) n (x))

x \to 4 lim (f (x) x)

x \to 2 lim (\frac{2 x}{x + 2})

What is the limit as x approaches 0+of (-2ln(x))^x ?
The limit as x approaches 0+of (-2ln(x))^x is Does not exist