What is (\partial)/(\partial x)(y/(2x)-1) ?

The answer to (\partial)/(\partial x)(y/(2x)-1) is -y/(2x^2)

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(\partial)/(\partial x)(y/(2x)-1)

\frac{\partial}{\partial x} (\frac{y}{2 x} - 1)

- \frac{y}{2 x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{y}{2 x} - 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{y}{2 x}) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (\frac{y}{2 x}) = - \frac{y}{2 x ^{2}}

\frac{\partial}{\partial x} (1) = 0

= - \frac{y}{2 x ^{2}} - 0

Simplify

= - \frac{y}{2 x ^{2}}

\frac{\partial}{\partial x} (2 π \frac{x}{y})

2 y d x = 3 x d y

n = 1 \sum \infty \frac{1}{2 + 3 ^{n}}

t y^{^{'}} + (2 t^{2} + 1) y = 3 t

x, - 1, 2

What is (\partial)/(\partial x)(y/(2x)-1) ?
The answer to (\partial)/(\partial x)(y/(2x)-1) is -y/(2x^2)