What is the limit as x approaches 0 of (4x-x^2)/(2x) ?

The limit as x approaches 0 of (4x-x^2)/(2x) is 2

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limit as x approaches 0 of (4x-x^2)/(2x)

x \to 0 lim (\frac{4 x - x ^{2}}{2 x})

2

Solution steps

x \to 0 lim (\frac{4 x - x ^{2}}{2 x})

Simplify

\frac{4 x - x ^{2}}{2 x} : \frac{1}{2} (4 - x)

= x \to 0 lim (\frac{1}{2} (4 - x))

Plug in the value

x = 0

= \frac{1}{2} (4 - 0)

Simplify

\frac{1}{2} (4 - 0) : 2

= 2

x \to 0 lim (\frac{e ^{- 6 x} - 1}{x})

x \to 0 + lim ([ln (x)]^{x})

x \to \infty + lim (x b)

x \to 3 - lim (3)

x \to 4 lim (\frac{1}{x - 2})

What is the limit as x approaches 0 of (4x-x^2)/(2x) ?
The limit as x approaches 0 of (4x-x^2)/(2x) is 2