What is the derivative of 139+(36/x+(x^2)/(16)) ?

The derivative of 139+(36/x+(x^2)/(16)) is x/8-(36)/(x^2)

What is the first derivative of 139+(36/x+(x^2)/(16)) ?

The first derivative of 139+(36/x+(x^2)/(16)) is x/8-(36)/(x^2)

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\frac{d}{d x} (139 + \frac{36}{x} + \frac{x ^{2}}{16})

\frac{x}{8} - \frac{36}{x ^{2}}

Solution steps

\frac{d}{d x} (139 + \frac{36}{x} + \frac{x ^{2}}{16})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (139) + \frac{d}{d x} (\frac{36}{x}) + \frac{d}{d x} (\frac{x ^{2}}{16})

\frac{d}{d x} (139) = 0

\frac{d}{d x} (\frac{36}{x}) = - \frac{36}{x ^{2}}

\frac{d}{d x} (\frac{x ^{2}}{16}) = \frac{x}{8}

= 0 - \frac{36}{x ^{2}} + \frac{x}{8}

Simplify

= \frac{x}{8} - \frac{36}{x ^{2}}

\int \frac{x ^{2}}{5 + x} d x

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\int (x^{2} + x) \cdot e^{2 x} d x

\int - \frac{e ^{2 x}}{1 + e ^{x}} d x

x \to 0 + lim ((tan (6 x))^{x})

What is the derivative of 139+(36/x+(x^2)/(16)) ?
The derivative of 139+(36/x+(x^2)/(16)) is x/8-(36)/(x^2)
What is the first derivative of 139+(36/x+(x^2)/(16)) ?
The first derivative of 139+(36/x+(x^2)/(16)) is x/8-(36)/(x^2)