What is the limit as t approaches 0 of (sin^2(t))/t ?

The limit as t approaches 0 of (sin^2(t))/t is 0

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limit as t approaches 0 of (sin^2(t))/t

t \to 0 lim (\frac{sin ^{2} ( t )}{t})

0

Solution steps

t \to 0 lim (\frac{sin ^{2} ( t )}{t})

Apply L'Hopital's Rule

: t \to 0 lim (\frac{sin ( 2 t )}{1})

= t \to 0 lim (\frac{sin ( 2 t )}{1})

Plug in the value

t = 0

= \frac{sin ( 2 \cdot 0 )}{1}

Simplify

\frac{sin ( 2 \cdot 0 )}{1} : 0

= 0

x \to - 1 lim (8 x^{2} + 7 x - 3)

x \to 2 lim (\frac{( x ^{3} - 3 x ^{2} + 4 )}{x ^{3} - 7 x ^{2} + 16 x - 12})

x \to - \infty lim (e^{x t})

x \to \infty lim (3 + \frac{6}{x})

b \to \infty lim (sin (b))

What is the limit as t approaches 0 of (sin^2(t))/t ?
The limit as t approaches 0 of (sin^2(t))/t is 0