What is the limit as x approaches 0 of (sin(16x))/x ?

The limit as x approaches 0 of (sin(16x))/x is 16

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limit as x approaches 0 of (sin(16x))/x

x \to 0 lim (\frac{sin ( 16 x )}{x})

16

Solution steps

x \to 0 lim (\frac{sin ( 16 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{cos ( 16 x ) \cdot 16}{1})

= x \to 0 lim (\frac{cos ( 16 x ) \cdot 16}{1})

Plug in the value

x = 0

= \frac{cos ( 16 \cdot 0 ) \cdot 16}{1}

Simplify

\frac{cos ( 16 \cdot 0 ) \cdot 16}{1} : 16

= 16

x \to 0 lim (6^{x} - 3^{x})

x \to - \infty lim (b^{x})

x \to 1 + lim (x^{\frac{1}{l n ( x )}})

x \to 0 lim (sin (x))

x \to 1 + lim (1 + \frac{1}{( x + 1 )})

What is the limit as x approaches 0 of (sin(16x))/x ?
The limit as x approaches 0 of (sin(16x))/x is 16