What is the limit as x approaches 1 of e^{x/(x-1)} ?

The limit as x approaches 1 of e^{x/(x-1)} is diverges

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limit as x approaches 1 of e^{x/(x-1)}

x \to 1 lim (e^{\frac{x}{x - 1}})

diverges

Solution steps

x \to 1 lim (e^{\frac{x}{x - 1}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (e^{\frac{x}{x - 1}}) = \infty

x \to 1 - lim (e^{\frac{x}{x - 1}}) = 0

= diverges

x \to 0 lim (x^{2} + 7 x + 5)

x \to \infty lim (x - \frac{16}{3})

x \to 0 + lim ((1 - 6 x)^{\frac{5}{x}})

x \to \infty lim (x^{7} - 7 x)

x \to 0 + lim (ln (1 + x))

What is the limit as x approaches 1 of e^{x/(x-1)} ?
The limit as x approaches 1 of e^{x/(x-1)} is diverges