What is the limit as x approaches 0 of (x^2-9)/x ?

The limit as x approaches 0 of (x^2-9)/x is diverges

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limit as x approaches 0 of (x^2-9)/x

x \to 0 lim (\frac{x ^{2} - 9}{x})

diverges

Solution steps

x \to 0 lim (\frac{x ^{2} - 9}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{x ^{2} - 9}{x}) = - \infty

x \to 0 - lim (\frac{x ^{2} - 9}{x}) = \infty

= diverges

x \to \infty lim (x^{4} - 4 x)

x \to - 3 lim (x^{4} + 2 x^{2} + 3 x - 3)

x \to 8 lim (4)

x \to \infty lim (\frac{( sin ( x ) - cos ( x ) )}{x})

t \to 0 + lim (cos (t))

What is the limit as x approaches 0 of (x^2-9)/x ?
The limit as x approaches 0 of (x^2-9)/x is diverges