What is the limit as s approaches 1+of (ins)/(s-1) ?

The limit as s approaches 1+of (ins)/(s-1) is infinity

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limit as s approaches 1+of (ins)/(s-1)

s \to 1 + lim (\frac{in s}{s - 1})

\infty

Solution steps

s \to 1 + lim (\frac{in s}{s - 1})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= in \cdot s \to 1 + lim (\frac{s}{s - 1})

Divide by highest denominator power:

\frac{1}{1 - \frac{1}{s}}

= in \cdot s \to 1 + lim (\frac{1}{1 - \frac{1}{s}})

For

s

approaching

1

from the right

, s > 1 \Rightarrow 1 - \frac{1}{s} > 0

The denominator is a positive quantity approaching 0 from the right

= in \cdot \infty

Simplify

in \cdot \infty : \infty

= \infty

x \to 0 - lim (x^{2} - \frac{5}{x})

y \to 0 lim (x sin (\frac{1}{y}))

x \to 2 lim (x (x - 5) + 8)

x \to 2 lim (\frac{\frac{8}{x} - 4}{2 - x})

θ \to 0 lim (\frac{tan ( 7 θ )}{θ})

What is the limit as s approaches 1+of (ins)/(s-1) ?
The limit as s approaches 1+of (ins)/(s-1) is infinity