What is the solution for y^{''}+10y=0,y(0)=2,y^'(0)=10 ?

The solution for y^{''}+10y=0,y(0)=2,y^'(0)=10 is y=2cos(sqrt(10)t)+sqrt(10)sin(sqrt(10)t)

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y^{''}+10y=0,y(0)=2,y^'(0)=10

y^{^{''}} + 10 y = 0, y (0) = 2, y^{^{'}} (0) = 10

y = 2 cos (10 t) + 10 sin (10 t)

Solution steps

y^{''} (t) + 10 y = 0

Solve linear ODE:

y = 2 cos (10 t) + 10 sin (10 t)

y = 2 cos (10 t) + 10 sin (10 t)

\int tan^{7} (x) sec^{17} (x) d x

s (t) = \frac{1}{t ^{2} + 6 t - 7}

\int \frac{ln ( 4 x )}{x} d x

\frac{\partial}{\partial x} (- \frac{2 y}{x ^{2} + y ^{2} + 1})

\int e^{7 x} cos (8 x) d x

What is the solution for y^{''}+10y=0,y(0)=2,y^'(0)=10 ?
The solution for y^{''}+10y=0,y(0)=2,y^'(0)=10 is y=2cos(sqrt(10)t)+sqrt(10)sin(sqrt(10)t)