What is the limit as x approaches 2 of 5/(4x-8) ?

The limit as x approaches 2 of 5/(4x-8) is diverges

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limit as x approaches 2 of 5/(4x-8)

x \to 2 lim (\frac{5}{4 x - 8})

diverges

Solution steps

x \to 2 lim (\frac{5}{4 x - 8})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{5}{4 x - 8}) = \infty

x \to 2 - lim (\frac{5}{4 x - 8}) = - \infty

= diverges

x \to 7 lim (13)

x \to - 1 lim (- x + 8)

x \to 0 lim ((1 + x^{2})^{3})

x \to 1 lim (\frac{1}{x} + ln (x))

x \to 1 lim (- x^{2} + 4 x - 5)

What is the limit as x approaches 2 of 5/(4x-8) ?
The limit as x approaches 2 of 5/(4x-8) is diverges