What is the integral from-1 to 0 of 7x ?

The integral from-1 to 0 of 7x is -7/2

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integral from-1 to 0 of 7x

\int_{- 1}^{0} 7 x d x

- \frac{7}{2}

Decimal Notation

- 3.5

Solution steps

\int_{- 1}^{0} 7 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{- 1}^{0} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 1}^{0}

= 7 [\frac{x ^{2}}{2}]_{- 1}^{0}

Compute the boundaries:

- \frac{1}{2}

= 7 (- \frac{1}{2})

Simplify

= - \frac{7}{2}

\int (e^{x^{2}}) d x

y = (2 x + 1) (x - 2)^{3}

\frac{\partial}{\partial x} ((1 - e^{- x}) (1 - e^{- y}))

- csc^{2} (x)

\frac{d y}{d x} = 9 x + y - 9