What is the limit as x approaches 0 of+(1+1/x)^x ?

The limit as x approaches 0 of+(1+1/x)^x is Does not exist

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limit as x approaches 0 of+(1+1/x)^x

x \to 0 lim (+ (1 + \frac{1}{x})^{x})

Does not exist

Solution steps

x \to 0 lim ((1 + \frac{1}{x})^{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((1 + \frac{1}{x})^{x}) = 1

x \to 0 - lim ((1 + \frac{1}{x})^{x}) =

Does not exist

= Does not exist

x \to 0 + lim (x ln (\frac{1}{x ^{2}}))

x \to 2 lim (3 + x - 2)

x \to 2 + lim (\frac{x + 2}{x - 2})

x \to \frac{1}{3} lim (ln (x))

x \to 2 lim (\frac{1}{x + 3} + 5)

What is the limit as x approaches 0 of+(1+1/x)^x ?
The limit as x approaches 0 of+(1+1/x)^x is Does not exist