What is the limit as x approaches 0 of (x^2-2x)/(4x) ?

The limit as x approaches 0 of (x^2-2x)/(4x) is -1/2

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limit as x approaches 0 of (x^2-2x)/(4x)

x \to 0 lim (\frac{x ^{2} - 2 x}{4 x})

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

x \to 0 lim (\frac{x ^{2} - 2 x}{4 x})

Simplify

\frac{x ^{2} - 2 x}{4 x} : \frac{1}{4} (x - 2)

= x \to 0 lim (\frac{1}{4} (x - 2))

Plug in the value

x = 0

= \frac{1}{4} (0 - 2)

Simplify

\frac{1}{4} (0 - 2) : - \frac{1}{2}

= - \frac{1}{2}

x \to 2 lim (\frac{1}{( x - 2 ) 2})

x \to 0 + lim ((x - 3) x)

t \to 0 lim (\frac{4 ^{t} - 3 ^{t}}{t})

x \to 0 - lim (\frac{x ^{3} - 2}{x})

x \to \infty lim (\frac{5 x ^{4} + 2 x}{x ^{2}})

What is the limit as x approaches 0 of (x^2-2x)/(4x) ?
The limit as x approaches 0 of (x^2-2x)/(4x) is -1/2