What is the limit as x approaches 0 of 1/(3^{1/x)+1} ?

The limit as x approaches 0 of 1/(3^{1/x)+1} is diverges

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limit as x approaches 0 of 1/(3^{1/x)+1}

x \to 0 lim (\frac{1}{3 ^{\frac{1}{x}} + 1})

diverges

Solution steps

x \to 0 lim (\frac{1}{3 ^{\frac{1}{x}} + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{3 ^{\frac{1}{x}} + 1}) = 0

x \to 0 - lim (\frac{1}{3 ^{\frac{1}{x}} + 1}) = 1

= diverges

x \to 1 lim (5 - x^{2})

x \to π lim (π - x)

x \to 0 + lim ((- 8 ln (x))^{x})

x \to 5 lim (x^{2} + 5 x - 20)

x \to 3 lim (2 x^{4} - 3 x^{2} - x + 1)

What is the limit as x approaches 0 of 1/(3^{1/x)+1} ?
The limit as x approaches 0 of 1/(3^{1/x)+1} is diverges