What is the derivative of (2x^2-7sqrt(x)+6^2) ?

The derivative of (2x^2-7sqrt(x)+6^2) is 16x^3-14x^{3/2}-56xsqrt(x)+49+48x-(42)/(sqrt(x))

What is the first derivative of (2x^2-7sqrt(x)+6^2) ?

The first derivative of (2x^2-7sqrt(x)+6^2) is 16x^3-14x^{3/2}-56xsqrt(x)+49+48x-(42)/(sqrt(x))

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\frac{d}{d x} ((2 x^{2} - 7 x + 6)^{2})

16 x^{3} - 14 x^{\frac{3}{2}} - 56 x x + 49 + 48 x - \frac{42}{x}

Solution steps

\frac{d}{d x} ((2 x^{2} - 7 x + 6)^{2})

Apply the chain rule:

2 (2 x^{2} - 7 x + 6) \frac{d}{d x} (2 x^{2} - 7 x + 6)

= 2 (2 x^{2} - 7 x + 6) \frac{d}{d x} (2 x^{2} - 7 x + 6)

\frac{d}{d x} (2 x^{2} - 7 x + 6) = 4 x - \frac{7}{2 x}

= 2 (2 x^{2} - 7 x + 6) (4 x - \frac{7}{2 x})

Simplify

2 (2 x^{2} - 7 x + 6) (4 x - \frac{7}{2 x}) : 16 x^{3} - 14 x^{\frac{3}{2}} - 56 x x + 49 + 48 x - \frac{42}{x}

= 16 x^{3} - 14 x^{\frac{3}{2}} - 56 x x + 49 + 48 x - \frac{42}{x}

7

f (x) = 6 - x

\frac{\partial}{\partial y} (y^{2} - 4 x)

\frac{d y}{d t} = y^{\frac{1}{3}} t^{\frac{2}{5}}

What is the derivative of (2x^2-7sqrt(x)+6^2) ?
The derivative of (2x^2-7sqrt(x)+6^2) is 16x^3-14x^{3/2}-56xsqrt(x)+49+48x-(42)/(sqrt(x))
What is the first derivative of (2x^2-7sqrt(x)+6^2) ?
The first derivative of (2x^2-7sqrt(x)+6^2) is 16x^3-14x^{3/2}-56xsqrt(x)+49+48x-(42)/(sqrt(x))