What is the limit as x approaches-3 of 1/(9-x^2) ?

The limit as x approaches-3 of 1/(9-x^2) is diverges

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limit as x approaches-3 of 1/(9-x^2)

x \to - 3 lim (\frac{1}{9 - x ^{2}})

diverges

Solution steps

x \to - 3 lim (\frac{1}{9 - x ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 3 + lim (\frac{1}{9 - x ^{2}}) = \infty

x \to - 3 - lim (\frac{1}{9 - x ^{2}}) = - \infty

= diverges

x \to 3 lim (x^{2} - 2 x + 3)

t \to 3 lim (\frac{1}{t - 3})

x \to 0 lim (x + x^{2})

x \to - 1 lim ((x + 3 x^{5})^{4})

x \to - \infty lim (- 3 \cdot (x))

What is the limit as x approaches-3 of 1/(9-x^2) ?
The limit as x approaches-3 of 1/(9-x^2) is diverges