What is the limit as x approaches 3 of x/(x^2-4x+3) ?

The limit as x approaches 3 of x/(x^2-4x+3) is diverges

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limit as x approaches 3 of x/(x^2-4x+3)

x \to 3 lim (\frac{x}{x ^{2} - 4 x + 3})

diverges

Solution steps

x \to 3 lim (\frac{x}{x ^{2} - 4 x + 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x}{x ^{2} - 4 x + 3}) = \infty

x \to 3 - lim (\frac{x}{x ^{2} - 4 x + 3}) = - \infty

= diverges

x \to 0 lim (\frac{( x ^{2} )}{x})

x \to 0 lim (\frac{3 x - 1}{x})

x \to 0 lim (400 x + 104000)

x \to - 4 lim ((1 + x)^{2})

x \to 3 - lim (x + 5)

What is the limit as x approaches 3 of x/(x^2-4x+3) ?
The limit as x approaches 3 of x/(x^2-4x+3) is diverges